第一知识网
www.001rz.com用因式分解法解下列方程: (1)9(x-3)平方=4(x-2)平方 (2)(x-1)平方-4(1-x)+4=0
日期:2021-07-05 10:47:31 人气:106
(1)9(x-3)平方=4(x-2)平方
9(x-3)²-4(x-2)²=0
[3(x-3)+2(x-2)][3(x-3)-2(x-2)]=0
(5x-13)(x-5)=0
x=13/5 x=5
(2)(x-1)平方-4(1-x)+4=0
(x-1)²+4(x-1)+4=0
[(x-1)+2]²=0
(x+1)²=0
x=-1
x(2x+1
9(x-3)²-4(x-2)²=0
[3(x-3)+2(x-2)][3(x-3)-2(x-2)]=0
(5x-13)(x-5)=0
x=13/5 x=5
(2)(x-1)平方-4(1-x)+4=0
(x-1)²+4(x-1)+4=0
[(x-1)+2]²=0
(x+1)²=0
x=-1
x(2x+1